A) \[C{{N}^{-}}\], CO
B) \[N{{O}^{+}},\,\,C{{O}^{+}}\]
C) \[C{{N}^{-}}\], \[O_{2}^{+}\]
D) CO, \[O_{2}^{+}\]
Correct Answer: A
Solution :
\[C{{N}^{-}}=14\]electrons ; CO =14 electrons B.O. =\[\frac{1}{2}[10-4]=\frac{6}{2}=3\].You need to login to perform this action.
You will be redirected in
3 sec