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JEE Main & Advanced Chemistry States of Matter / पदार्थ की अवस्थाएँ - गैस एवं द्रव Question Bank Molecular speeds

  • question_answer
    The root mean square velocity of an ideal gas in a closed container of fixed volume is increased from \[5\times {{10}^{4}}\,cm\,{{s}^{-1}}\] to \[10\times {{10}^{4}}\,cm\,{{s}^{-1}}\]. Which of the following statement correctly explains how the change is accomplished [Pb. CET 1986]

    A)                 By heating the gas, the temperature is doubled

    B)                 By heating the gas, the pressure is quadrupled (i.e. made four times)

    C)                 By heating the gas, the temperature is quadrupled

    D)                 By heating the gas, the pressure is doubled

    Correct Answer: B

    Solution :

                    \[\frac{{{U}_{1}}}{{{U}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\therefore \frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{5\times {{10}^{4}}}{10\times {{10}^{4}}} \right)}^{2}}=\frac{1}{4}\]


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