Answer:
(i) Average velocity of the plane
\[=\frac{Total\,\,displacement\,\,of\,\,the\,\,plane}{Total\,time\,\,taken}\]
\[=\frac{260km}{30\min }=\frac{260\times 60}{30}km/hr\]
\[=520km/hr\] Patna to Ranchi
(ii) Average velocity of the bus
\[=\frac{Total\,\,displacement\,\,of\,the\,bus}{Total\,\,time\,\,taken}\]
\[=\frac{260km}{8hr}=32.5\,\,km/hr\]Patna to Ranchi.
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