question_answer

The figure given below shows a velocity-time graph of a car starting from rest. The graph has three sections OA, AB and BC. Compare the distance travelled in section AB with the distance travelled in section OA.

Answer:

Distance travelled in section BC = Area covered BC line with time axis. \[=(2t-t)\times ({{v}_{0}}-0)=t\times {{v}_{0}}=t{{v}_{0}}\] Distance travelled in section AB = Area of triangle under AB \[=\frac{1}{2}\times t\times {{v}_{0}}=\frac{t{{v}_{0}}}{2}\] \[\therefore \]Distance travelled in section BC to AB \[=t{{V}_{0}}:\frac{t{{V}_{0}}}{2}=1:\frac{1}{2}=2:1\]