Answer:
Initial position = X Final position = Y Magnitude of displacement \[XY=?\]
From figure,\[XY=XZ+ZY=2XZ\,\,or\,\,\,2ZY\]
(according to hint given)
Consider \[\Delta OZX,\,\,\sin 60{}^\circ \,=\frac{XZ}{r}XZ=r\sin 60{}^\circ \]
\[=\frac{r\sqrt{3}}{2}\]
\[\therefore XY=2XY=2\times \frac{r\sqrt{3}}{2}=\sqrt{3}r\]
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