Answer:
Let the car accelerate for a time t. Suppose the maximum velocity attained by the car be v.
Then\[v=\alpha \,\,{{t}_{1}}\,\,or\,\,{{t}_{1}}=\frac{v}{\alpha }\]
Let the car decelerate for a time\[S=ut+\frac{1}{2}a{{t}^{2}}\].
Then\[0=v-\beta \,\,{{t}_{2}}\,\,or\,\,{{t}_{2}}=\frac{v}{\beta }\]
Now\[t={{t}_{1}}+{{t}_{2}}=\frac{v}{\alpha }+\frac{v}{\beta }=t\]
\[\Rightarrow v=\left( \frac{\alpha \beta }{\alpha +\beta } \right)t\]
You need to login to perform this action.
You will be redirected in
3 sec