9th Class Science Time and Motion Question Bank Motion HOTS Subjective Problems

  • question_answer
    The displacement - time graph is shown below
     
    From the graph match the following given below
    List - A                     List - B
    (i) Velocity along AB    (a)\[\text{1}.\text{25 m}{{\text{s}}^{-\text{1}}}\]
    (ii) Velocity along DE       (b) Zero
    (iii) Average velocity along CE     (c)\[-\text{7}.\text{5 m}{{\text{s}}^{-\text{1}}}\]
      (d)\[\text{2}.\text{1m}{{\text{s}}^{-\text{1}}}\]

    Answer:

    (i) Velocity between ‘0’ to 2s \[=\frac{10-25}{2}=\frac{-15}{2}=-7.5m/s\] (ii) Velocity between ‘8s’ to 12s \[=\frac{final\,\,velocity\,\,initial\,\,velocity}{Total\,\,time\,\,taken}\] \[=\frac{25-20}{12-8}=\frac{5}{4}=1.25m/s\] (iii) Average velocity between 5s to 12s \[=\frac{displacement\,\,\operatorname{cov}ered}{Total\,time\,\,taken}=\frac{25-10}{12-5}\] \[=\frac{15}{7}=2.1m/s\]


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