Answer:
(i) IIT Foundation School width = 15m, the number rounds made by a teacher along the width 15m = 10 (i.e. even) the time period for the above duration = 9.30 - 8.00 = 90 min.
\[Average\text{ }speed=\frac{Total\text{ }distance\text{ }travelled}{Total\text{ }time\text{ }taken}\]
\[=\frac{15\times 10}{90}=(5/3)m/\min \]
(ii) Since teacher made even rounds, his final position is equal to the initial position.
hence displacement of a teacher is zero.
\[\therefore \]average velocity of a teacher is zero.
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