question_answer

Figure shows the graph of velocity versus time for a particle going along the x-axis. What is (a) the acceleration, (b) the distance travelled in 0 to 10s and (c) the displacement in 0 to 10s.

Answer:

                 (a) The acceleration of the particle = Slope of the straight line suppose slope at ‘c’ \[=\frac{8-2}{10-0}=\frac{6}{10}=0.6m/{{s}^{2}}\] (b) The area under the curve OACD gives the displacement of the particle. Hence, distance\[=\left( \frac{2+8}{2} \right)\times 10=50m\] (c) the above graph represents the uniform motion, hence distance and displacement of the particle is same = 50 m.