Answer:
Let\[{{V}_{1}}>{{V}_{2}}\]and let Car \[1({{V}_{3}})\] meet Car \[2({{V}_{2}})\] after a time t.
From figure, \[AC=AB+BC\]
\[\Rightarrow {{V}_{1}}\times 1={{V}_{2}}(1+t)+{{V}_{3}}t\Rightarrow t=1hr\]
\[\therefore 10={{V}_{2}}(1+t)\Rightarrow {{V}_{2}}=5km/hr.\]
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