A) \[y=3x\]
B) \[y=2x\]
C) \[y=x\]
D) \[y=4x\]
Correct Answer: D
Solution :
\[X=\frac{1}{2}a{{t}^{2}}=\frac{1}{2}\times a\times 100=50a\] \[Y=\frac{1}{2}a{{(20)}^{2}}=\frac{1}{2}a(400)=200a\] \[\frac{X}{Y}=\frac{50a}{200a}\] \[Y=4x\]You need to login to perform this action.
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