A) \[\text{1 m}/{{\text{s}}^{\text{2}}}\]
B) \[\text{2 m}/{{\text{s}}^{\text{2}}}\]
C) \[\text{1}/\text{2 m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{3 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: A
Solution :
\[x+48=v\times t\] \[v=36kmph\,=36\times \frac{5}{18}=10m/s\] \[t=105,\,\,a=?\] \[a=\frac{V-u}{t}=\frac{10-0}{10}=1m/{{s}^{2}}\]
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