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  5. Time and Motion

9th Class Science Time and Motion Question Bank Motion IIT JEE Objective Problems

  • question_answer
    Initial velocity of a particle moving along a straight line is 10 m/s and its retardation is\[\text{2 m}/{{\text{s}}^{\text{2}}}\]. Distance covered by the particle in the fifth second of its motion is

    A)  1 m  

    B)  19 m

    C)  50 m                    

    D)  75 m

    Correct Answer: A

    Solution :

    \[u=10m/s\] retardation is\[2m/{{s}^{2}}\] Distance travelled in 3th sec is \[{{S}_{nth}}=U+\left( \frac{a}{2} \right)(2n-1)\] \[=10+\left( -\frac{2}{2} \right)(2\times 5-1)=10-(10-1)\] \[=10-9=1m\]


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