Answer:
When two vectors of equal magnitude are inclined to each other at an angle of\[\text{12}0{}^\circ \], the magnitude of their resultant is equal to that of the either vector. \[{{a}^{2}}={{a}^{2}}+{{a}^{2}}+2{{a}^{2}}{{\cos }^{2}}\theta \] \[\Rightarrow \cos \theta =-\frac{1}{2}\]\[\Rightarrow \] \[\theta ={{120}^{\circ }}\]
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