Answer:
\[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] R will be minimum when \[\cos \theta =-1\] or \[\theta =\mathbf{18}{{\mathbf{0}}^{\mathbf{o}}}\] \[{{R}_{\min }}=A\tilde{\ }B.\]
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