Answer:
Maximum height attained, \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] Clearly, H will be maximum when \[\sin \theta =1\] \[\therefore \] \[{{H}_{\max }}=\frac{{{u}^{2}}}{2g}=h\] Maximum horizontal range, \[{{R}_{\max }}=\frac{{{u}^{2}}}{g}=2h\].
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