Answer:
The vertical component of velocity at the point of projection is \[\upsilon \] sin \[\theta \] and at the point of return is \[-\upsilon \] sin \[\theta \] . \[\therefore \] Magnitude of change in momentum \[=m(\upsilon \sin \theta +\upsilon \sin \theta )=2m\upsilon \sin \theta \] \[=2m\upsilon \sin {{45}^{\circ }}=\sqrt{2}m\upsilon \] (in the vertical direction).
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