A) \[E=0,\,B=0\]
B) \[E=0,\,B\ne 0\]
C) \[E\ne 0,\,B=0\]
D) \[E\ne 0,\,B\ne 0\]
Correct Answer: A
Solution :
Here the proton has no acceleration so \[E=B=0.\] When \[E=0\]but \[B\ne 0,\]but parallel to the motion of proton, there will be no force acting. When \[E\ne 0\]and \[B\ne 0\]and E, B and motion of proton \[\left( v \right)\]are mutually perpendicular, there may be no net force. Forces due to E and B cancel each other.
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