JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    Electrons move at right angles to a magnetic field of \[1.5\times {{10}^{-2}}\]Tesla with a speed of \[6\times {{10}^{7}}m/s.\]If the specific charge of the electron is \[1.7\times {{10}^{11}}\]C/kg. The radius of the circular path will be                                                         [BHU 2003]

    A)            2.9 cm                                     

    B)            3.9 cm

    C)            2.35 cm                                   

    D)            3 cm

    Correct Answer: C

    Solution :

               \[r=\frac{mv}{qB}=\frac{6\times {{10}^{7}}}{1.7\times {{10}^{11}}\times 1.5\times {{10}^{-2}}}=2.35\,cm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner