JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is proportional to      [CBSE PMT 2005]

    A)            \[\frac{B}{v}\]                     

    B)            \[\frac{v}{R}\]

    C)            \[\sqrt{\frac{v}{B}}\]        

    D)            \[\sqrt{\frac{B}{v}}\]

    Correct Answer: C

    Solution :

                       Electric current corresponds to the revolution of electron is \[i=\frac{ev}{2\pi r}\] Magnetic field due to circular current at the centre \[B=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\pi \,i}{r}=\frac{{{\mu }_{0}}}{4\pi }.\frac{ev}{{{r}^{2}}}\]Þ \[r=\sqrt{\frac{{{\mu }_{0}}}{4\pi }.\frac{ev}{B}}\]Þ \[r\propto \sqrt{\frac{v}{B}}\].


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