A) 1.6 ´ 1015 m / s
B) 6 ´ 10-16 m / s
C) 3.75 ´ 103 m / s
D) 3.75 ´ 102 m / s
Correct Answer: C
Solution :
When electron moves in both electric and magnetic field then \[qE=qvB\]. \ \[v=\frac{E}{B}=\frac{1500}{0.40}=3750\,\,m/s\]\[=3.75\times {{10}^{3}}m/s\].
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