JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    An electron is moving with a speed of \[{{10}^{8}}\,m/\sec \] perpendicular to a uniform magnetic field of intensity B. Suddenly intensity of the magnetic field is reduced to B/2. The radius of the path becomes from the original value of r [MP PET 1993]

    A)            No change                            

    B)            Reduces to r / 2

    C)            Increases to 2r                    

    D)            Stops moving

    Correct Answer: C

    Solution :

               \[r\propto \frac{1}{B}\] i.e. \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{{{B}_{2}}}{{{B}_{1}}}\Rightarrow {{r}_{2}}=\frac{{{B}_{1}}}{{{B}_{1}}/2}\times r\]= 2r


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