JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    A proton and an \[\alpha -\]particle enter a uniform magnetic field perpendicularly with the same speed. If proton takes 25 \[\mu \] sec to make 5 revolutions, then the periodic time for the \[\alpha -\]particle would be                                                                             [MP PET 1993]

    A)            50 \[\mu \] sec                    

    B)            25 \[\mu \] sec

    C)            10 \[\mu \] sec                    

    D)            5 \[\mu \] sec

    Correct Answer: C

    Solution :

               Time period of proton \[{{T}_{p}}=\frac{25}{5}=5\mu \,\sec \] By using \[T=\frac{2\pi \,m}{qB}\]\[\Rightarrow \]\[\frac{{{T}_{\alpha }}}{{{T}_{p}}}=\frac{{{m}_{\alpha }}}{{{m}_{p}}}\times \frac{{{q}_{p}}}{{{q}_{\alpha }}}\]\[=\frac{4{{m}_{p}}}{{{m}_{p}}}\times \frac{{{q}_{p}}}{2{{q}_{p}}}\] \[\Rightarrow \,\] \[{{T}_{\alpha }}=2{{T}_{p}}=10\mu \,\,\sec .\]


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