JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    An \[\alpha -\]particle travels in a circular path of radius 0.45 m in a magnetic field \[B=1.2\,Wb/{{m}^{2}}\] with a speed of \[2.6\times {{10}^{7}}\,m/\sec \]. The period of revolution of the \[\alpha -\]particle is

    A)            \[1.1\times {{10}^{-5}}\,\sec \]                                        

    B)            \[1.1\times {{10}^{-6}}\sec \]

    C)            \[1.1\times {{10}^{-7}}\,\sec \]                                        

    D)            \[1.1\times {{10}^{-8}}\,\sec \]

    Correct Answer: C

    Solution :

               \[T=\frac{2\pi m}{qB}=\frac{2\pi r}{v}=\frac{2\times 3.14\times 0.45}{2.6\times {{10}^{7}}}=1.08\times {{10}^{-7}}\sec \]


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