A) 36.7 m
B) 36.7 cm
C) 3.67 m
D) 3.67 cm
Correct Answer: B
Solution :
\[r=\frac{\sqrt{2mK}}{qB}=\frac{1}{B}\sqrt{\frac{2mV}{q}}\] \[=\frac{1}{{{10}^{-3}}}\sqrt{\frac{2\times 9\times {{10}^{-31}}\times 12000}{1.6\times {{10}^{-19}}}}\]=0.367 m = 36.7 cmYou need to login to perform this action.
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