A) \[2.4\times {{10}^{-12}}\,N\]
B) \[0.24\times {{10}^{-12}}\,N\]
C) \[24\times {{10}^{-12}}\,N\]
D) \[0.024\times {{10}^{-12}}\,N\]
Correct Answer: A
Solution :
\[F=qvB\sin \theta \] \[=1.6\times {{10}^{-19}}\times 2\times {{10}^{7}}\times 1.5\ \sin \ {{30}^{o}}\] \[=1.6\times {{10}^{-19}}\times 2\times {{10}^{7}}\times 1.5\times \frac{1}{2}=2.4\times {{10}^{-12}}N\]
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