A) \[6.25\times {{10}^{3}}\,tesla\] in \[\hat{z}-\]direction
B) \[{{10}^{-15}}\,tesla\] in \[\hat{z}-\]direction
C) \[6.25\times {{10}^{-3}}\,tesla\] in \[\hat{z}-\]direction
D) \[{{10}^{-3}}\,tesla\] in \[\hat{z}-\]direction
Correct Answer: D
Solution :
\[F=qvB\sin \theta \] Þ \[B=\frac{F}{qv\sin \theta }\] \[{{B}_{\min }}=\frac{F}{qv}\] (when q = 90o) \[\therefore \ {{B}_{\min }}=\frac{F}{qv}=\frac{{{10}^{-10}}}{{{10}^{-12}}\times {{10}^{5}}}={{10}^{-3}}\] Tesla in \[U=\frac{{{B}^{2}}}{2{{\mu }_{0}}},\]-direction.
You need to login to perform this action.
You will be redirected in
3 sec
