JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    A proton and a deutron both having the same kinetic energy, enter perpendicularly into a uniform magnetic field B. For motion of proton and deutron on circular path of radius \[{{R}_{p}}\] and \[{{R}_{d}}\] respectively, the correct statement is [MP PET 1995]

    A)            \[{{R}_{d}}=\sqrt{2}\,{{R}_{p}}\]                                     

    B)            \[{{R}_{d}}={{R}_{p}}/\sqrt{2}\]

    C)            \[{{R}_{d}}={{R}_{p}}\]    

    D)            \[{{R}_{d}}=2{{R}_{p}}\]

    Correct Answer: A

    Solution :

                       \[\frac{m{{v}^{2}}}{R}=qvB\]. For proton \[{{R}_{p}}=\frac{mv}{qB}=\frac{\sqrt{2{{m}_{p}}E}}{qB}\] and for deutron \[{{R}_{d}}=\frac{\sqrt{2{{m}_{d}}E}}{qB}\] \[\Rightarrow \,\ \frac{{{R}_{d}}}{{{R}_{p}}}=\sqrt{\frac{{{m}_{d}}}{{{m}_{p}}}}=\sqrt{2}\Rightarrow {{R}_{d}}=\sqrt{2}{{R}_{p}}\]


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