JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    A beam of ions with velocity \[2\times {{10}^{5}}\,m/s\] enters normally into a uniform magnetic field of \[4\times {{10}^{-2}}\,tesla\]. If the specific charge of the ion is \[5\times {{10}^{7}}\,C/kg\], then the radius of the circular path described will be                                         [NCERT 1983; BVP 2003]

    A)            0.10 m                                     

    B)            0.16 m

    C)             0.20 m                                    

    D)            0.25 m

    Correct Answer: A

    Solution :

               \[r=\frac{mv}{Bq}\]\[=\frac{v}{(q/m)B}=\frac{2\times {{10}^{5}}}{5\times {{10}^{7}}\times 4\times {{10}^{-2}}}=0.1m\]


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