JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    An electron is accelerated by a potential difference of 12000 volts. It then enters a uniform magnetic field of \[{{10}^{-3}}\,T\] applied perpendicular to the path of electron. Find the radius of path. Given mass of electron \[=9\times {{10}^{-31}}\,kg\] and charge on electron \[=1.6\times {{10}^{-19}}\,C\]                               [MP PET 1997]

    A)            36.7 m                                     

    B)            36.7 cm

    C)            3.67 m                                     

    D)            3.67 cm

    Correct Answer: B

    Solution :

     \[r=\frac{\sqrt{2mK}}{qB}=\frac{1}{B}\sqrt{\frac{2mV}{q}}\]            \[=\frac{1}{{{10}^{-3}}}\sqrt{\frac{2\times 9\times {{10}^{-31}}\times 12000}{1.6\times {{10}^{-19}}}}\]=0.367 m = 36.7 cm


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