A) \[5\times {{10}^{-11}}\,N\] along \[\hat{i}\]
B) \[5\times {{10}^{3}}\] N along \[\hat{k}\]
C) \[5\times {{10}^{-11}}\,N\] along \[-\hat{j}\]
D) \[5\times {{10}^{-4}}\,N\] along \[-\hat{k}\]
Correct Answer: D
Solution :
\[\overrightarrow{F}=q\,(\overrightarrow{v\,}\times \overrightarrow{B})={{10}^{-11}}({{10}^{8}}\hat{j}\,\times 0.5\hat{i})\] \[=5\times {{10}^{-4}}(\hat{j}\times \hat{i})=5\times {{10}^{-4}}N(-\hat{k})\]
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