A) \[3\times {{10}^{-12}}N\]
B) \[5\times {{10}^{-12}}N\]
C) \[6\times {{10}^{-12}}\]N
D) \[9\times {{10}^{-12}}N\]
Correct Answer: B
Solution :
\[F=qvB\sin \theta =1.6\times {{10}^{-19}}\times 2.5\times 2.5\times {{10}^{7}}\sin {{30}^{o}}\] \[F=1.6\times {{10}^{-19}}\times 6.25\times {{10}^{7}}\times \frac{1}{2}=5\times {{10}^{-12}}N\]
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