A) 1
B) \[\frac{1}{2}\]
C) 2
D) \[\frac{1}{4}\]
Correct Answer: B
Solution :
\[r=\frac{p}{qB}\] Þ p µ q (\[\because \] r and B are constant) \[\frac{{{p}_{p}}}{{{p}_{\alpha }}}=\frac{{{q}_{p}}}{{{q}_{\alpha }}}=\frac{{{q}_{p}}}{(2{{q}_{p}})}=\frac{1}{2}\]
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