A) \[H{{e}^{+}}\] ions will be deflected more than those of \[{{O}^{2+}}\]
B) \[H{{e}^{+}}\]ions will be deflected less than those of \[{{O}^{2+}}\]
C) All the ions will be deflected equally
D) No ions will be deflected
Correct Answer: C
Solution :
\[r=\frac{\sqrt{2mK}}{qB}\Rightarrow r\ \propto \ \frac{\sqrt{m}}{q}\Rightarrow \frac{{{r}_{H{{e}^{+}}}}}{{{r}_{{{O}^{++}}}}}=\sqrt{\frac{{{m}_{H{{e}^{+}}}}}{{{m}_{{{O}^{++}}}}}}\times \frac{{{q}_{{{O}^{++}}}}}{{{q}_{H{{e}^{+}}}}}\] \[=\sqrt{\frac{4}{16}}\times \frac{2}{1}=\frac{1}{1}.\] Then will deflect equally.
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