A) \[{{10}^{-3}}Wb/{{m}^{2}}\]
B) \[{{10}^{3}}Wb/{{m}^{2}}\]
C) \[{{10}^{5}}Wb/{{m}^{2}}\]
D) \[{{10}^{16}}Wb/{{m}^{2}}\]
Correct Answer: B
Solution :
Since particle is moving undeflected. So \[qE=qvB\Rightarrow B=E/v=\frac{{{10}^{4}}}{10}={{10}^{3}}Wb/{{m}^{2}}\]You need to login to perform this action.
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