A) Straight line along the x-direction
B) A circle in the xz-plane
C) A circle in the yz-plane
D) A circle in the xy-plane
Correct Answer: B
Solution :
\[\overrightarrow{F}=-e(\overrightarrow{v}\times \overrightarrow{B})\]Þ \[\overrightarrow{F}=-e[v\hat{i}\times B\hat{j}]=evB[-\hat{k}]\] i.e. Force on electron is acting towards negative z-axis. Hence particle will move on a circle in xz-plane.You need to login to perform this action.
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