JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Motion of Charged Particle In Magnetic Field

  • question_answer
    A particle of charge \[-16\times {{10}^{-18}}\]coulomb moving with velocity \[10\,\,m{{s}^{-1}}\] along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude \[{{10}^{4}}\,\,V/m\]is along the negative    z-axis. If the charged particle continues moving along the   x-axis, the magnitude of B is                                                           [AIEEE 2003]

    A)            \[{{10}^{-3}}Wb/{{m}^{2}}\]

    B)            \[{{10}^{3}}Wb/{{m}^{2}}\]

    C)            \[{{10}^{5}}Wb/{{m}^{2}}\]   

    D)            \[{{10}^{16}}Wb/{{m}^{2}}\]

    Correct Answer: B

    Solution :

                       Since particle is moving undeflected. So \[qE=qvB\Rightarrow B=E/v=\frac{{{10}^{4}}}{10}={{10}^{3}}Wb/{{m}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner