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JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Motion of Satellite

  • question_answer
    In a satellite if the time of revolution is T, then K.E. is proportional to                     [BHU 1995]

    A)             \[\frac{1}{T}\]

    B)             \[\frac{1}{{{T}^{2}}}\]

    C)             \[\frac{1}{{{T}^{3}}}\]      

    D)             \[{{T}^{-2/3}}\]

    Correct Answer: D

    Solution :

                    v \[=\sqrt{\frac{GM}{r}}\] \ \[K.E.\propto {{v}^{2}}\propto \frac{1}{r}\] and \[{{T}^{2}}\propto {{r}^{3}}\] \\[\,K.E.\,\propto {{T}^{-2/3}}\]


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