A) 10 hr
B) \[(6/\sqrt{2})\,hr\]
C) 6 hr
D) \[6\sqrt{2}\,hr\]
Correct Answer: D
Solution :
Distances of the satellite from the centre are 7R and 3.5R respectively. \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{3/2}}\,\Rightarrow {{T}_{2}}=24\,{{\left( \frac{3.5R}{7R} \right)}^{3/2}}=6\sqrt{2}\,hr\]
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