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JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Motion of Satellite

  • question_answer
     Two satellite A and B, ratio of masses 3 : 1 are in circular orbits of radii r and 4r. Then ratio of total mechanical energy of A to B is                               [DCE 2002]

    A) 1 : 3    

    B)             3 : 1

    C)             3 : 4    

    D)             12 : 1

    Correct Answer: D

    Solution :

                    Total mechanical energy of satellite             \[E=\frac{-GMm}{2r}\]Þ \[\frac{{{E}_{A}}}{{{E}_{B}}}=\frac{{{m}_{A}}}{{{m}_{B}}}\times \frac{{{r}_{B}}}{{{r}_{A}}}\]Þ\[\frac{3}{1}\times \frac{4r}{r}\]=\[\frac{12}{1}\]


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