JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Motion of Satellite

  • question_answer
    If the gravitational force between two objects were proportional to 1/R (and not as \[1/{{R}^{2}})\] where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to [CBSE PMT 1994; JIPMER 2001, 02]

    A)             \[1/{{R}^{2}}\]       

    B)             \[{{R}^{0}}\]

    C)             \[{{R}^{1}}\]          

    D)             1/R

    Correct Answer: B

    Solution :

                    Gravitational force provides the required centripetal force for orbiting the satellite             \[\frac{m{{v}^{2}}}{R}=\frac{K}{R}\]     because \[\left( F\propto \frac{1}{R} \right)\] \ \[v\propto R{}^\circ \]


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