A) \[-0.5\,mg{{R}_{e}}\]
B) \[-mg{{R}_{e}}\]
C) \[-2\,mg{{R}_{e}}\]
D) \[4\,mg{{R}_{e}}\]
Correct Answer: A
Solution :
Potential energy = \[\frac{-GMm}{r}=\frac{GMm}{{{R}_{e}}+h}=\frac{-GMm}{2{{R}_{e}}}\] = \[-\frac{gR_{e}^{2}m}{2{{R}_{e}}}\]\[=-\frac{1}{2}mg{{R}_{e}}\]\[=-0.5mg{{R}_{e}}\]
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