JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Motion of Satellite

  • question_answer
    An earth satellite S has an orbit radius which is 4 times that of a communication satellite C. The period of revolution of S is                          [MP PMT 1994; DCE 1999]

    A) 4 days 

    B)             8 days

    C)             16 days

    D)               32 days

    Correct Answer: B

    Solution :

                    Time period of communication satellite \[{{T}_{c}}=1\ \text{day}\] Time period of another satellite = \[{{T}_{s}}\]             \[\frac{{{T}_{s}}}{{{T}_{c}}}={{\left( \frac{{{r}_{s}}}{{{r}_{c}}} \right)}^{3/2}}={{(4)}^{3/2}}\Rightarrow {{T}_{s}}={{T}_{c}}\times {{(4)}^{3/2}}=8\ \text{days}\text{.}\]


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