A) \[\frac{1}{T}\]
B) \[\frac{1}{{{T}^{2}}}\]
C) \[\frac{1}{{{T}^{3}}}\]
D) \[{{T}^{-2/3}}\]
Correct Answer: D
Solution :
v \[=\sqrt{\frac{GM}{r}}\] \ \[K.E.\propto {{v}^{2}}\propto \frac{1}{r}\] and \[{{T}^{2}}\propto {{r}^{3}}\] \\[\,K.E.\,\propto {{T}^{-2/3}}\]You need to login to perform this action.
You will be redirected in
3 sec