A) 100%
B) 41.4%
C) 50%
D) 59.6%
Correct Answer: B
Solution :
\[{{v}_{e}}=\sqrt{2}{{v}_{0}}=1.414\ {{v}_{0}}\] Fractional increase in orbital velocity\[\left( \frac{\Delta v}{v} \right)\] \[=\frac{{{v}_{e}}-{{v}_{0}}}{{{v}_{0}}}=0.414\] Percentage increase = 41.4%You need to login to perform this action.
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