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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Motion on Inclined Surface

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    A body is sliding down an inclined plane having coefficient of friction 0.5.  If the normal reaction is twice that of the resultant downward force along the incline, the angle between the inclined plane and the horizontal is                                                          [EAMCET (Engg.) 2000]

    A)             \[{{15}^{o}}\]         

    B)             \[{{30}^{o}}\]

    C)             \[{{45}^{o}}\]

    D)             \[{{60}^{o}}\]

    Correct Answer: C

    Solution :

                    Resultant downward force along the incline             \[=mg(\sin \theta -\mu \cos \theta )\]                Normal reaction \[=mg\cos \theta \]             Given : \[mg\cos \theta =2mg(\sin \theta -\mu \cos \theta )\]             By solving \[\theta ={{45}^{o}}\].  


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