JEE Main & Advanced
Physics
NLM, Friction, Circular Motion
Question Bank
Motion on Inclined Surface
question_answer
A 2 kg mass starts from rest on an inclined smooth surface with inclination 30o and length 2 m. How much will it travel before coming to rest on a frictional surface with frictional coefficient of 0.25 [UPSEAT 2003]
A) 4 m
B) 6 m
C) 8 m
D) 2 m
Correct Answer:
A
Solution :
\[{{v}^{2}}={{u}^{2}}+2as=0+2\times g\sin 30\]\[\times 2\] Þ \[v=\sqrt{20}\] Let it travel distance ?S? before coming to rest \[S=\frac{{{v}^{2}}}{2\mu g}=\frac{20}{2\times 0.25\times 10}=4m\]