A) 4 m
B) 6 m
C) 8 m
D) 2 m
Correct Answer: A
Solution :
\[{{v}^{2}}={{u}^{2}}+2as=0+2\times g\sin 30\]\[\times 2\] Þ \[v=\sqrt{20}\] Let it travel distance ?S? before coming to rest \[S=\frac{{{v}^{2}}}{2\mu g}=\frac{20}{2\times 0.25\times 10}=4m\]You need to login to perform this action.
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