Answer:
From\[S=ut+\frac{1}{2}a{{t}^{2}}\]
\[\Rightarrow 150=10u+\frac{1}{2}a{{(10)}^{2}}\]
\[\Rightarrow 150=10u+50a\] …..(1)
From \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\]
\[\Rightarrow 24=u+\frac{a}{2}(2\times 10-1)\]
\[\Rightarrow 48=2u+19a\] …..(2)
On solving equations (1) and (2) \[u=5\,m{{s}^{-1}}\]and\[a=2\,m{{s}^{-2}}\]
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