Answer:
(a) \[Average\,velocity=\frac{total\,\,displacement}{time}\] from the given graph Average velocity \[=\frac{100}{10}=10m/s\] (b) Instantaneous velocity at any time is equal to the slope of that line at \[A=\frac{50}{2.5}=20m/s\] at 5 sec instantaneous velocity = zero. Since slope along AB is zero. at 12 sec, = slope\[=\frac{0-100}{5a}=-20m/s\]
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